UVa 1185 - Big Number

The number of digits in a number X =	CEILING[log(X)] and N! =(N * N-1 * N-2 ... * 1) Thus, the number of digits in N! =	CEILING[log(N!)] =	CEILING[log(N * (N-1) * ... * 1)] =	CEILING[log(N) +log (N-1) ... +log(1)]