SPOJ CRYPTO1

Summary
Given the result of applying a simple cryptographic function $$f(n)$$, where $$n$$ is the number of seconds from midnight 1970.01.01 GMT to a certain date, we need to find the original date.

$$f(n) =  n^2 \; mod \; 4000000007$$

Explanation
An integer $$q$$ is called a quadratic residue modulo $$n$$ if it is congruent to a perfect square (mod $$n$$); i.e. if there exists an integer x such that:

$$x^2\equiv q \; (mod \; n).$$

When $$q$$ and $$n$$ are mutually prime, it is solvable if $$ a^{p-1} \equiv +1 \; (mod \; p)$$. It will always be $$1$$ or $$-1$$, because of Fermat's Little Theorem. When p is of the form $$4k+3$$ (like 4000000007), the solutions will be $$ x = a^{k+1} \; (mod \; p)$$ and $$x = -a^{k+1} \; (mod \; p)$$. Only one of these will fit in the given range.

Gotchas

 * If you are using your programming language's date feature, make sure to take care of time-zones.

Implementation
You can use the string "%a %b %d %T %Y" for the "strftime" function.

Input
1749870067

Output
Sun Jun 13 16:20:39 2004